The point moves along a circle of radius R = 0.5 m with a constant tangential acceleration

The point moves along a circle of radius R = 0.5 m with a constant tangential acceleration of 2 m / s2 from rest. Determine the normal acceleration of a point at time t = 1 s.

To find the normal acceleration of a given point, we will use the formula: an = V ^ 2 / R = (aτ * t) 2 / R.

Variable values: aτ – constant tangential acceleration (aτ = 2 m / s2); t – moment in time (t = 1 s); R is the radius of the circle (R = 0.5 m).

Calculation: an = (aτ * t) ^ 2 / R = (2 * 1) ^ 2 / 0.5 = 8 m / s2.

Answer: After 1 second, the normal acceleration of the target point was 8 m / s2.