The point moves along a curve with a constant tangential acceleration ai = 0.5m / s2.

The point moves along a curve with a constant tangential acceleration ai = 0.5m / s2. Determine the total acceleration a of the point on the curve section with the radius of curvature R = 2m, if the point moves in this section with the speed V = 5m / s.

To find the full acceleration of a given point, we will use the formula: a = √ (at ^ 2 + at ^ 2) = √ (at ^ 2 + (V ^ 2 / R) ^ 2).

Variable values: at – constant tangential acceleration (at = 0.5 m / s2); V – speed on the curve section (V = 5 m / s); R is the radius of the site (R = 2 m).

Calculation: a = √ (at ^ 2 + (V ^ 2 / R) ^ 2) = √ (0.5 ^ 2 + (5 ^ 2/2) ^ 2) = 12.51 m / s2.

Answer: The full acceleration of the set point is 12.51 m / s2.