The point moves along a straight line according to the equation x = At + Br³, where A = 6 m / s, B = 0.125

The point moves along a straight line according to the equation x = At + Br³, where A = 6 m / s, B = 0.125 m / s³. Determine the average speed of the point in the time interval from t = 2 s to t = 6 s.

Given: the equation of motion of a given point: x = At + Bt ^ 3; A (first coefficient) = 6 m / s; B (second coefficient) = 0.125 m / s3; t1 (initial time value) = 2 s; t2 (end value) = 6 s.

Since the given point is constantly moving in a positive direction, then to find the average speed of the given point, we apply the formula: Vav. = S / t = (x (t2) – x (t1)) / (t2 – t1) = (6 * 6 + 0.125 * 6 ^ 3 – 6 * 2 – 0.125 * 2 ^ 3) / (6 – 2) = 50/4 = 12.5 m / s.

Answer: In the considered time interval, the given point moved at an average speed of 12.5 m / s.



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