The point moves in a straight line according to the law s = 4t + 5 Find the instantaneous speed of the point

The point moves in a straight line according to the law s = 4t + 5 Find the instantaneous speed of the point at the moments of time t = 3, t = 5 Accelerations at both of these moments.

V (t) = S ‘(t); / instantaneous velocity is equal to the first derivative of the law of motion of the body, in this case the point

a (t) = V ‘(t) = S’ ‘(t); / acceleration is equal to the first derivative of the velocity or the second derivative of the law of motion.

V (t) = (4t + 5) ‘= (4t)’ + 5 ‘= 4;

a (t) = 4 ‘= 0;

Thus, the speed of a point moving according to this law is constant at any time, and the acceleration is equal to 0.