The point moves in a straight line according to the law S = 6t ^ 2-3t + 54. At time t = 5.

The point moves in a straight line according to the law S = 6t ^ 2-3t + 54. At time t = 5. At what point in time will the body stop.

Since the velocity is the first-order derivative of the path traveled by the body, then to find the velocity function, we take the variable from the function S = 6t ^ 2 – 3t + 54.

S (t) ‘= V = (6t ^ 2 – 3t + 54)’ = 2 * 6 * t – 1 * 3 + 0 = 12t – 3.

When the body stops V = 0 m / s.

Let’s calculate the time for the body to stop:

12t – 3 = 0.

12t = 3.

t = 3/12 = 0.25 s.

Answer: The body will stop at time t = 0.25 s.