The point moves uniformly accelerated from the state of rest and travels 100m in 10 seconds.
| April 25, 2021 | education
The point moves uniformly accelerated from the state of rest and travels 100m in 10 seconds. What is the speed at the moment when the point has passed 25m.
To find the speed of a given point after passing 25 m of the path, we apply the formula: S = V2 / 2a = V ^ 2 / (2 * (2S1 / t1 ^ 2)) = V ^ 2 * t1 ^ 2 / 4S1, whence we express: V = √ (S * 4S1 / t1 ^ 2).
Values of variables: S – considered path (S = 25 m); S1 – common track (S1 = 100 m); t1 is the duration of the common path by the point (t1 = 10 s).
Calculation: V = √ (25 * 4 * 100/10 ^ 2) = 10 m / s.
Answer: After 25 meters of travel, the set point will have a speed of 10 m / s.
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