The point oscillates with an amplitude of A = 0.04m and a period of T = 2s.

The point oscillates with an amplitude of A = 0.04m and a period of T = 2s. write the equation of these oscillations, assuming that at the time t = 0 the displacement X (0) = 0 and X (0) ≤0.

The dependence of the coordinate x of a material point on time t, performing harmonic oscillations, looks as follows x (t) = А ∙ sin (ω ∙ t), where ω is the cyclic frequency of oscillations, A is the amplitude value of the coordinate. From the condition of the problem it is known that the point oscillates with amplitude A = 0.04 m, period T = 2 s, and at time t = 0 with displacement x (0) = 0 m.To write the equation of these oscillations, it is necessary to determine ω according to the formula ω = 2 ∙ π / Т, where the constant value is π ≈ 3.14. We get ω = 2 ∙ π / 2 = π (rad / s), x (t) = 0.04 ∙ sin (π ∙ t).

Answer: the equation of oscillations has the form – x (t) = 0.04 ∙ sin (π ∙ t).