The pool is filled with two pipes operating simultaneously in 4 hours. In how many hours can the first pipe fill the pool

The pool is filled with two pipes operating simultaneously in 4 hours. In how many hours can the first pipe fill the pool, acting separately, if it fills the pool 6 hours longer than the second?

X-hours during which the pool is filled with the first pipe
X + 6 second pipe
(1 / x + 1 / x + 6) * 4 = 1
X ^ 2-2x-24
X = 6, second root is less than 0
Answer 6 and 12



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