The potential difference between the plates of a 0.1 μF capacitor has changed by 175 V.

The potential difference between the plates of a 0.1 μF capacitor has changed by 175 V. Determine the change in the capacitor charge.

Initial data: Δ (φ1 – φ2) – change in the potential difference between the capacitor plates (175 V); C is the capacitance of the capacitor (0.1 μF).

SI system: C = 0.1 μF = 0.1 * 10-6 F.

The change in the charge of a capacitor can be determined by the formula: Δq = Δ (φ1 – φ2) * C.

Let’s perform the calculation: Δq = 175 * 0.1 * 10-6 = 17.5 * 10-6 = 17.5 μC.

Answer: The change in the charge of the capacitor is 17.5 μC.