The power of the electric iron is 0.6 kW. Calculate the work of the current in it for 1.5 hours. How much energy is consumed?

Electric iron power:
P = A / t, where P is the power of the electric iron (P = 0.6 kW = 0.6 * 10 ^ 3 W), A is the work of the current in the electric iron (J), t is the operating time of the iron (t = 1 , 5 h = 1.5 * 60 * 60 = 5400 s).
Work current:
A = P * t = (0.6 * 10 ^ 3) * 5400 = 3420000 J = 3.42 MJ.
Power consumption of the electric iron:
E = P * t, t = 1.5 hours.
E = P * t = (0.6 * 10 ^ 3) * 1.5 = 900 W / h = 0.9 kW / h.
Answer: The work of the current in an electric iron is 3.42 MJ, the power consumption is 0.9 kW / h.