The precipitate of 2,4,6-tribromophenol with a substance amount of 0.3 mol is formed by the interaction
| March 18, 2021 | education
The precipitate of 2,4,6-tribromophenol with a substance amount of 0.3 mol is formed by the interaction of bromine water with phenol. Find the mass of phenol.
C6H5OH + 3Br2 → C6H2 (Br) 3OH + 3HBrn (C6H5OH) = n (C6H2 (Br) 3OH = 0.3 molM (C6H5OH) = 94 g / molm (C6H5OH) = 94 * 0.3 = 28.2 g
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