The pressure of kerosene in the vessel is 50 Pa. How will the pressure change if the same volume

The pressure of kerosene in the vessel is 50 Pa. How will the pressure change if the same volume of water is poured instead of kerosene?

It is known that the pressure of kerosene in a vessel with a base area S is p1 = 50 Pa. To find out how the pressure will change, if instead of kerosene, pour the same volume of water V = S ∙ h, knowing that the density of water ρ2 = 1000 kg / m ^ 3, and kerosene ρ1 = 800 kg / m ^ 3, you first need to calculate the pressure water in this vessel: p2 = ρ2 ∙ g ∙ h2 = ρ2 ∙ g ∙ (V / S). For both liquids V and S, which means that g ∙ (V / S) does not change, we express g ∙ (V / S) = p2 / ρ2 = p1 / ρ1. Hence, p2 = (p1 / ρ1) ∙ ρ2 = (50/800) ∙ 1000 = 62.5 Pa. The pressure increased by 62.5 – 50 = 12.5 (Pa).