The primary winding of a step-down transformer with a transformation ratio k = 10 is connected to an alternating

The primary winding of a step-down transformer with a transformation ratio k = 10 is connected to an alternating current network with a voltage of U1 = 120 V. The resistance of the secondary winding is R2 = 1.2 Ohm, the current in it is I2 = 5.0 A. Find the resistance of the load connected to the secondary transformer winding.

Given:
k = 10
U₁ = 120 B
R₂ = 1.2 Ohm
I₂ = 5.0 A
Rн -?
Solution: 1) U₂ = U₁ / k = 120/10 = 12V
2) (R₂ + Rн) = U₂ / I₂
R₂ + Rн = 12 / 5.0 = 2.4 Ohm
3) Rn = 2.4 – R₂ = 2.4 – 1.2 = 1.2 Ohm



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