The primary winding of the step-up transformer contains 100 turns and the secondary one 1000. The voltage in the primary circuit is 120 V. What is the voltage in the secondary circuit if there is no energy loss?
Initial data: N1 (the number of turns the primary winding contains) = 100 turns; N2 (number of turns in the second winding) = 1000 turns; U1 (voltage in the primary circuit) = 120 V; no energy loss.
The voltage in the secondary circuit is determined from the equality: K (transformation ratio) = U1 / U2 = N1 / N2, whence U2 = U1 * N2 / N1.
Calculation: U2 = 120 * 1000/100 = 1200 V (1.2 kV).
Answer: The voltage in the secondary circuit is 1.2 kV.
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