The primary winding of the transformer contains 1800 turns and the secondary 60 turns. What is the current in the secondary winding if the current in the primary winding is 0.1 amperes.
The power on the primary winding is equal to the power on the second less losses. Efficiency losses are not mentioned, so there are no losses. Efficiency = 100%.
The voltage on the second winding is equal to the voltage in the first, divided by the transformation ratio. This coefficient is equal to the ratio of the number of turns in the first winding to the number of turns in the second.
N1 = 1800
N2 = 60
I1 = 0.1A
N1 / N2 = I2 / I1
Final calculations in the task:
hence I2 = (I1 × N1) / N2 = 0.1 × 1800/60 = 3A
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