The probability of breaking the first computer is 0.2; for the second – 0.15. What is the probability

The probability of breaking the first computer is 0.2; for the second – 0.15. What is the probability that the following will break down: 1) both computers; 2) none; 3) only one 4) at least one

1) 1 computer and 2 computer broke down: P = P1 * P2 = 0.2 * 0.15 = 0.03.

2) 1 computer did not break and computer 2 did not break down: P = (1 – P1) * (1 – P2) = 0.8 * 0.85 = 0.68.

3) 1 computer broke, 2 whole or 2 computer broke, 1 whole: P = P1 * (1 – P2) + P2 * (1 – P1) = 0.2 * 0.85 + 0.15 * 0.8 = 0.29.

4) 1 computer broke, 2 whole or 2 computer broke, 1 whole, or two computers broke: P = P1 * (1 – P2) + P2 * (1 – P1) + P1 * P2 = 0.2 * 0.85 + 0.15 * 0.8 + 0.2 * 0.15 = 0.32.