The probability of getting off the bus at the next stop for each passenger is 0.6.

The probability of getting off the bus at the next stop for each passenger is 0.6. Find the probability that out of 5 passengers are standing. Find the probability that out of 5 passengers standing at the entrance, at least one will leave at the bus stop.

The probability of getting off the bus at the next stop for each passenger is p = 0.6.
The likelihood that the passenger will not get out:
q = 1 – p = 1 – 0.6 = 0.4.
The probability that none of the 5 passengers will get off at the next stop:
P (0) = q ^ 5 = 0.4 ^ 5 = 0.0102.
The probability of an opposite event such that at least one passenger will get off at the next stop:
P (> 0) = 1 – P (0) = 1 – 0.0102 = 0.9898;
Answer: 0.9898.