The probability of getting off the bus at the next stop for each passenger is 0.6. Find the probability that out of 5 passengers are standing. Find the probability that out of 5 passengers standing at the entrance, at least one will leave at the bus stop.
The probability of getting off the bus at the next stop for each passenger is p = 0.6.
The likelihood that the passenger will not get out:
q = 1 – p = 1 – 0.6 = 0.4.
The probability that none of the 5 passengers will get off at the next stop:
P (0) = q ^ 5 = 0.4 ^ 5 = 0.0102.
The probability of an opposite event such that at least one passenger will get off at the next stop:
P (> 0) = 1 – P (0) = 1 – 0.0102 = 0.9898;
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