The probability of hitting the target by the first shooter is 0.5, and the second shooter is 0.3. The arrows fired at the same time.

The probability of hitting the target by the first shooter is 0.5, and the second shooter is 0.3. The arrows fired at the same time. What is the likelihood that one of them hits the target and the other misses?

The probability of hitting the target for the first shooter is p1 = 0.5.
The probability of a miss for the first shooter is q1 = 1 – p1 = 1 – 0.5 = 0.5.
The probability of hitting the target for the second shooter is p2 = 0.3.
The probability of a miss for the second shooter is q2 = 1 – p2 = 1 – 0.3 = 0.7.
The probability that only one shooter will hit is obtained by the theorem of addition of inconsistent events:
P = p1 q2 + q1 p2 = 0.5 0.7 + 0.5 0.3 = 0.5.
Answer: The probability that one shooter will hit the target and the other will not hit P = 0.5.



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