The probability of hitting the target by the first shooter is 0.8, and the second is 0.7. The shooters fire one shot

The probability of hitting the target by the first shooter is 0.8, and the second is 0.7. The shooters fire one shot at the target at a time. Determine the likelihood that the target will be hit if the shooters shoot independently of each other

Let P be an event – the target will be hit.
The probability of hitting the target at the first shooter:
p1 = 0.8;
Miss chance:
q1 = 1 – p1 = 1 – 0.8 = 0.2;
The probability of hitting the target at the second shooter:
p2 = 0.7;
Miss chance:
q2 = 1 – p2 = 1 – 0.7 = 0.3;
The probability of the event P` that not a single shot hit the target:
P` = q1 * q2 = 0.2 * 0.3 = 0.06;
Then the probability of the event P that the target will be hit:
P = 1 – P` = 1 – 0.06 = 0.94.
Answer: 0.94.