The probability of winning per ticket is 0.13. What is the probability of at least one win for the owner of five tickets?

univerkov | August 8, 2021 | education

The probability of winning is p = 0.13.
The probability of not winning q = 1 – p = 1 – 0.13 = 0.87.
Probability that no ticket will win:
P5 (0) = q ^ 5 = 0.87 ^ 5 = 0.498.
The probability of an opposite event such that at least one ticket is winning.
P`5 (0) = 1 – P5 (0) = 1 – 0.498 = 0.502.
Answer: 0.502.

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