The probability that a mistake will be made in the audit is p = 0.028. Three independent checks were made.

The probability that a mistake will be made in the audit is p = 0.028. Three independent checks were made. Find the probability that only one of them will be wrong.

The probability that an error will not be made during verification is: q = 1 – p = 1 – 0.028 = 0.972.
The probability that only one error will be made during three checks is determined by the Bernoulli formula:
P3 (1) = C (3.1) * p ^ 1 * q ^ 2 = 3 * 0.028 * 0.972 ^ 2 = 0.079.
Answer: The probability that only one mistake will be made is 0.079.