The probability that the student will pass the first exam is 0.9; second 0.9; third 0.8.
| July 9, 2021 | education
The probability that the student will pass the first exam is 0.9; second 0.9; third 0.8. Find the probability that a student will pass three exams.
Events such that the student passes the first exam – A, the second – B, the third – C – independent events. The probability of their joint offensive is equal to the product of their probabilities.
P (ABC) = P (A) * P (B) * P (C) = 0.9 * 0.9 * 0.8 = 0.648.
Answer: The probability that a student will pass three exams is 0.648.
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