The process is isochoric. After increasing the temperature by 1.3 times, the gas pressure in the vessel increased
| March 31, 2021 | education
The process is isochoric. After increasing the temperature by 1.3 times, the gas pressure in the vessel increased by 150 kPa. Find the initial pressure in the vessel.
Given: isochoric process (V = const); T2 (end temperature) = 1.3T1 (start temperature); ΔP (pressure increase) = 150 kPa.
To find the required initial pressure of the taken gas, we apply the proportion: P1 / T1 = P2 / T2.
Substitute the known values: P1 / T1 = (P1 + 150) / 1.3T1.
1.3P1 = P1 + 150.
0.3 P1 = 150 and P1 = 150 / 0.3 = 500 kPa.
Answer: The initial pressure of the taken gas in the vessel was 500 kPa.
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