The projectile in flight exploded into two fragments, which scatter in opposite directions so that the first

| September 10, 2021 | education

The projectile in flight exploded into two fragments, which scatter in opposite directions so that the first fragment continues to move along the trajectory. Determine the velocity of the projectile if the velocity of the fragments is v1 = 1500 m / s v2 = 500 m / s and the mass of the first fragment is 0.3 of the mass of the projectile.

V1 = 1500 m / s. V2 = 500 m / s. m1 = 0.3 * m. V -? Let’s use the law of conservation of momentum for a closed system: m * V = m1 * V1 – m2 * V2. We put the sign “-” because the fragments fly in different directions. Let’s find the mass of the second fragment: m1 = 0.3 * m. : m2 = m – m1 = m – 0.3 * m = 0.7 * m. m * V = 0.3 * m * V1 – 0.7 * m * V2. V = (0.3 * m * V1 – 0.7 * m * V2) / m. V = 0.3 * V1 – 0.7 * V2. V = 0.3 * 1500 m / s – 0.7 * 500 m / s = 100 m / s.
Answer: the speed of the fragment to rupture is V = 100 m / s.



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