The propeller carriage under the action of the force F = 1 kN. The frictional force of the obstacle to its movement
| November 25, 2020 | education
The propeller carriage under the action of the force F = 1 kN. The frictional force of the obstacle to its movement is equal to 200 N. Chim is equal to the equal action of these forces.
Given:
F = 1kN = 1000N
Ftr = 200N
Decision:
Because The vectors of the two forces are directed in opposite directions, then the resultant of these forces is equal to their difference. R = F-Ftr = 1000N-200N = 800N
Answer: 800N
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