The pulley makes 300 revolutions in 0.5 minutes. Determine the period of its rotation.
| December 19, 2020 | education
Given:
N = 300 turns;
t = 0.5 min = 30 s.
Find: T =?
Decision:
T = t / N
T = 30/300 = 0.1 s
Answer: the period of rotation of this pulley is T = 0.1 s.
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