The pump delivers 25 liters of water per second to the tower, what work will it do in 2 hours if the tower is 10 m high.

V = 25 l = 25 * 10 ^ -3 m ^ 3.

ρ = 1000 kg / m ^ 3.

g = 9.8 m / s ^ 2.

t1 = 1 s.

t = 2 h = 7200 s.

h = 10 m.

A -?

The work of pump A to lift water into the tower will be determined by the formula: A = m * g * h, where m is the mass of the lifted water, g is the acceleration of gravity, h is the height of the tower.

Let us find the mass of water m, which the pump lifts during time t according to the formula: m = m1 * t, where m1 is the mass of water lifted by the pump during time t1.

m1 = ρ * V.

The formula for determining the operation of the pump will take the form: A = ρ * V * t * g * h.

A = 1000 kg / m ^ 3 * 25 * 10 ^ -3 m ^ 3 * 7200 s * 9.8 m / s ^ 2 * 10 m = 708050 J.

Answer: the pump is doing work A = 708050 J.