The quadrilateral ABCD is described around a circle. Find sides AB and CD if BC = 6cm AD = 9cm

The quadrilateral ABCD is described around a circle. Find sides AB and CD if BC = 6cm AD = 9cm AB is 2 times more than CD.

Since the quadrilateral is described around a circle, then the sum of the lengths of the opposite sides is equal.

AD + BC = AB + CD.

Let the length of the segment CD be equal to X cm, then, by condition, the length of the segment AB will be equal to 2 * X cm.

Then 9 + 6 = X + 2 * X.

3 * X = 15.

X = CD = 15/3 = 5 cm.

AB = 2 * CD = 2 * 5 = 10 cm.

Answer: The length of the segment AB is 10 cm, the length of the segment CD is 5 cm.