The quadrilateral ABCD is inscribed in a circle. You know that angle B is 33 ° greater than angle D. Find angle D.
If a quadrilateral is inscribed in a circle, then the sum of its opposite angles is 180.
Let the angle ADC = X0, then the angle ABC, by condition, will be equal to (X + 33).
180 = X + X + 33.
2 * X = 180 – 33.
2 * X = 147.
X = 147/2 = 73.50.
Angle ADC = 73.50.
Answer: The ADC angle is 73.50.
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