The radii of the base of the truncated cone are 10 cm and 4 cm, and the height is 8 cm. find the generator of the cone.

The height BH divides the radius OA into segments AH and OH.

Since BO1OH is a quadrangle, OH = BO1 = 4 cm.

Then AH = AO – OH = 10 – 4 = 6 cm.

In a right-angled triangle ABH, according to the Pythagorean theorem, we determine the length of the hypotenuse AB, which is the sought generator of the cone.

AB ^ 2 = BH ^ 2 + AH ^ 2 = 36 + 64 = 100.

AB = 10 cm.

Answer: The length of the generatrix is 10 cm.



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