The radius inscribed in a right-angled triangle of a circle is equal to half

The radius inscribed in a right-angled triangle of a circle is equal to half the difference between the legs. Find the ratio of the larger leg to the smaller leg.

By condition, R = (AC – AB) / 2.

Since the circle is inscribed in a right-angled triangle, then R = (AC + AB – BC) / 2.

By the Pythagorean theorem, BC = √ (AC ^ 2 + AB ^ 2).

Then (AC – AB) / 2 = (AC + AB – √ (AC ^ 2 + AB ^ 2)) / 2.

2 * AB = √ (AC ^ 2 + AB ^ 2).

4 * AB ^ 2 = AC ^ 2 + AB ^ 2.

3 * AB ^ 2 = AC ^ 2.

AC ^ 2 / AB ^ 2 = 3.

AC / AB = √3.

Answer: The leg ratio is √3 / 1.



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