The radius of a circle inscribed in a square is 4.5 cm. Find the perimeter of the square

The diagonal of the inscribed square is the diameter of the inscribed circle, then the diagonal AC = 2 * R = 2 * 4.5 = 9 cm.

Triangle ABC is rectangular and isosceles, AB = BC as sides of a square, then 2 * AB ^ 2 = AC ^ 2 = 81.

AB = 9 / √2 cm

Then Ravsd = 4 * AB = 4 * 9 / √2 = 4 * 9 * √2 / 2 = 18 * √2 cm.

Answer: The perimeter of the square is 18 * √2 cm.



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