The radius of one circle is 6 cm, and the radius of the other is 2 cm. How many times is the length

The radius of one circle is 6 cm, and the radius of the other is 2 cm. How many times is the length of the first circle greater than the length of the other?

The length of the larger circle is: L = 2 * π * R.
The length of the smaller circle is: l = 2 * π * r.
The ratio of the length of the larger circle to the length of the smaller circle
L / l = 2 * π * R / (2 * π * r) = R / r = 6/2 = 3.
Thus, the length of the first circle is 3 times the length of the other.



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