The radius of the ball is 10 cm at what distance from the center of the ball you need

The radius of the ball is 10 cm at what distance from the center of the ball you need to draw a plane so that the cross-sectional area of the ball by this plane is 36P cm ^ 2.

Let us define its radius through the sectional area.

Ssection = π * R ^ 2 = π * CO1 ^ 2 = 36 * π cm2.

CO1 = 6 cm.

From the center of the sphere, point O, we construct the radius of the OS.

In a right-angled triangle COO1, according to the Pythagorean theorem, OO1 ^ 2 = CO ^ 2 – CO1 ^ 2 = 100 – 36 = 64.

OO1 = 8 cm.

Answer: From the center of the sphere to a section of 8 cm.



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