The radius of the base of the cone is 20. Through the middle of the height of the cone

The radius of the base of the cone is 20. Through the middle of the height of the cone, a plane is drawn parallel to the base. Then the cross-sectional area is equal to.

A section parallel to the base is a circle.

The area of the circle is found by the formula: S = 2nR².

Let A – the top of the cone, AO – the height of the cone, AB – the radius of the base, AB = 20, point O1 – the midpoint of the height AO. О1В1 – section radius.

Consider triangles AOB and AO1B1: angle A is common, angle O is equal to angle O1 (= 90 °). This means that triangles are similar in two angles. Since O1 is the middle of AO, the similarity coefficient is:

k = AO / AO1 = 2. Hence, OB / O1B1 = 2, hence O1B1 = 10.

Find the cross-sectional area: S = 2 * n * 10 = 20n.



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