The radius of the base of the cone is 4 cm, the axial section is an equilateral triangle. Find the area of the axial section.

univerkov | June 12, 2021 | education

Determine the diameter of the circle at the base of the cone.

D = AC = 2 * R = 2 * 4 = 8 cm.

By condition, the axial section of the cone is an equilateral triangle, then AB = BC = AC = 8 cm, and all its internal angles are 60.

Then the axial section area is equal to:

Ssection = AB * AC * Sin60 / 2 = 8 * 8 * √3 / 4 = 16 * √3 cm2.

Answer: The axial section area is 16 * √3 cm2.

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