The radius of the circle centered at point O is 16. Find the chord AB, if the angle AOB = 60 degrees.

Given: circle, radius O = 16 angle AOB = 60
aichi: AB-?
Solution: arc AB = 60 ‘tk angle AOB-central arc CB = 180 arc CA = arc CB- arc AB = 180′-60’ = 120 ‘angle ABO = 120’ / 2 = 60 ‘- (forgot the name) => isosceles triangle AOB with base OB => AB = OA = 16



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