The radius of the circle with center O is 16. Find the chord AB if the angle AOB = 60 degrees

From the center of the circle, point O, draw the radii OA and OB.

The AOB triangle is isosceles, since OB = OA = R = 13 cm.

Then AB is the base, and the angle OAB = OBA = (180 – AOB) / 2 = (180 – 60) / 2 = 120/2 = 60.

Then the triangle AOB is isosceles, since all its internal angles are 60, and then the chord AB = OA = R = 13 cm.

Answer: The length of the chord AB is 13 cm.



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