The reaction involved 13 g of zinc and hydrochloric acid. As a result of the reaction, hydrogen and zinc

The reaction involved 13 g of zinc and hydrochloric acid. As a result of the reaction, hydrogen and zinc chloride were formed. Determine the volume and number of hydrogen molecules. 1) Write down the reaction equation (coefficients) 2) Calculate the amount of zinc substance 3) Calculate the amount of hydrogen 4) Calculate the volume of hydrogen 5) Calculate the number of hydrogen molecules

The reaction between zinc and sulfuric acid is described by the following chemical reaction equation.

Zn + H2SO4 = ZnSO4 + H2;

1 mole of metal reacts with 1 mole of acid. In this case, 1 mol of salt is synthesized and 1 mol of gaseous hydrogen is released.

Let’s calculate the chemical amount of a substance in 13 grams of zinc.

M Zn = 65 grams / mol;

N Zn = 13/65 = 0.2 mol;

The same chemical amount of hydrogen will be obtained.

Let’s calculate its volume.

Under normal conditions, one liter of ideal gas assumes a volume of 22.4 liters.

V H2 = 0.2 x 22.4 = 4.48 liters;

One mole contains 6.022 x 10 ^ 23 molecules.

The number of hydrogen molecules will be:

N H2 = 0.2 x 6.022 x 10 ^ 23 = 1.2 x 10 ^ 22 molecules;