The reaction involved 13 g of zinc and hydrochloric acid. The reaction produced hydrogen and zinc chloride

The reaction involved 13 g of zinc and hydrochloric acid. The reaction produced hydrogen and zinc chloride. Determine the volume and number of hydrogen molecules. 1) Write down the reaction equation (coefficients!) 2) Calculate the amount of zinc substance: 3) Calculate the amount of hydrogen: 4) Calculate the volume of hydrogen: 5) Calculate the number of hydrogen molecules

1) Zn + 2HCl = ZnCl₂ + H₂

2) n (Zn) = 13/65 = 0.2 mol

3) n (H₂) = 0.2 mol

4) V (H₂) = 0.2 * 22.4 = 4.48 l

5) N (H₂) = 4.48 * 6 * 10 (23 degrees) / 22.4 = 1.2 * 10 (23 degrees)

Answer: V (H₂) = 4.48 l, N (H₂) = 22.4 = 1.2 * 10 (to the 23rd degree)