The reaction involved 13 g of zinc and hydrochloric acid. the reaction produced hydrogen

The reaction involved 13 g of zinc and hydrochloric acid. the reaction produced hydrogen and zinc chloride. determine the volume and number of hydrogen molecules.

Zn + 2HCl = ZnCl2 + H2.

It is known that from 65 g of zinc 2 g of hydrogen is formed (based on molar masses). Let us find the mass of hydrogen formed from 13 g of zinc:

65 g – 2 g

13 g – x g

Hence x = 13 * 2/65 = 0.4 g.

Now let’s find the amount of substance:

n = m / Mr = 0.4 / 2 = 0.2 mol.

Taking into account the fact that 1 mole of gas at normal conditions. occupies a volume of 22.4 liters, we determine the volume occupied by 0.2 mol:

V = 22.4 * n = 22.4 * 0.2 = 4.48 l.

The number of H2 molecules is found by the formula:

N = n * Na = 0.2 * 6.02 * 10 ^ 23 = 1.2 * 10 ^ 23.