The reaction involved 18 g of magnesium and hydrogen sulfide acid. The reaction produced hydrogen and magnesium sulfide.

The reaction involved 18 g of magnesium and hydrogen sulfide acid. The reaction produced hydrogen and magnesium sulfide. Determine the volume and amount of released hydrogen Mg + H2S- MgS + H2

Given:
m (Mg) = 18 g

Find:
V (H2) -?
n (H2) -?

1) Mg + H2S => MgS + H2;
2) n (Mg) = m / M = 18/24 = 0.75 mol;
3) n (H2) = n (Mg) = 0.75 mol;
4) V (H2) = n * Vm = 0.75 * 22.4 = 16.8 liters.

Answer: The volume of H2 is 16.8 liters; the amount of substance is 0.75 mol.