The reaction of zinc with hydrochloric acid formed 13.6 and zinc chloride, calculate the mass and amount of zinc reacted.

Let’s implement the solution:
1. In accordance with the condition, write the data:
Zn + 2HCl = ZnCl2 + H2 – substitutions, zinc chloride, hydrogen is released;
2. Calculations:
M (Zn) = 65.3 g / mol.
M (ZnCl2) = 136.3 g / mol.
3. Determine the amount of the original substance:
Y (ZnCl2) = m / M = 13.6 / 136.3 = 0.09 mol.
Y (Zn) = 0.09 mol since the amount of substances is 1 mol.
4. Find the mass of the metal:
m (Zn) = Y * M = 0.09 * 65.3 = 5.9 g.
Answer: to carry out the process, zinc is required in an amount of 0.09 mol, weighing 5.9 g.