The reaction proceeds according to the equation CO (g) + H2O (g) CO2 (g) + H2 (g). The initial
The reaction proceeds according to the equation CO (g) + H2O (g) CO2 (g) + H2 (g). The initial concentrations of the reacting substances are: = 0.01 mol / l; = 0.0201 mol / l; = 0.0101 mol / l; = 0.0101 mol / l. The equilibrium concentration of CO is equal to = 0.007 mol / l. Calculate the equilibrium constant of the reaction.
CO (g) + H2O (g) = CO2 (g) + H2 (g) C0, mol / L 0.01 0.0201 0.0101 0.0101 [C], mol / L 0.003 0.003 0.003 0.003 C, mol / L 0.007 0.0171 0.0071 0.0071
Since the equilibrium concentration of CO = 0.007 mol / L, we calculate the amount of reacted CO: [CO] = C0-C = 0.01-0.007 = 0.003 mol / L.
Since, according to the reaction equation, the ratio between the components is 1: 1: 1: 1, the amount of reacted H2O, CO2 and H2 will also be equal to 0.003.
Then: [H2O] = 0.0201-0.003 = 0.0171 mol / l
[CO2] = [H2] = 0.0101-0.003 = 0.0071 mol / L.
The equilibrium constant is calculated by the formula: Кр = ([CO2] * [H2]) / ([CO] * [H2O]) = 0.0071 ^ 2 / (0.0171 * 0.007) = 0.421