The reaction rate of СО2 (g.) + С (s) – 2СО (g) with a pressure increase by 4 times increases by …

When the pressure rises 4 times, the volume decreases 4 times, the CO2 concentration increases 4 times (since c = n / V)
According to the law of mass action: V (chemical p-ii) = c (CO2)
Because the concentration increased 4 times, the reaction rate also increased 4 times.



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