The rectangle has a length of 8 m more than its width. find the perimeter if the area is 345 m2

Let’s say that the width of the rectangle is x meters.

Since the length is 8 meters greater than the width, its value will be: x + 8 m.

The area is the product of the sides of the figure, so we get the following equation:

x * (x + 8) = 345.

x ^ 2 + 8 * x – 345 = 0.

D ^ 2 = 8 ^ 2 – 4 * 1 * (-345) = 64 + 1380 = 1444.

D = √1444 = 38.

x = (-8 + 38) / 2 = 30/2 = 15 cm (width).

x + 8 = 15 + 8 = 23 cm (length).

Determine the perimeter of the rectangle.

2 * (15 + 23) = 2 * 38 = 76 meters.

Answer: The perimeter is 76 m.