The rectangle is 14 m long and 2 times shorter in width. Find the perimeter and area of the rectangle.

1.To solve the problem, you need to know the width of the rectangle. From the condition, the length is known, as well as how many times it is greater than the width. Let’s find the width.

14/2 = 7 meters.

2. Let’s calculate what the perimeter is.

(14 + 7) * 2 = 42 meters.

3. Let’s find out its area.

14 * 7 = 98 m².

Answer: The perimeter of the rectangle is 42 meters, the area is 98 square meters.



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