The rectangle is 20% longer than the width. how many times is the rectangle longer than the width?

univerkov | March 8, 2021 | education

Let’s denote by x the width of this rectangle.
According to the condition of the problem, the length of this rectangle is 20% greater than its width, therefore the length of this rectangle is:
x + (20/100) * x = x + 0.2 * x = 1.2 * x.
Therefore, the length of this rectangle is 1.2 * x / x = 1.2 times its width.
Answer: the length of this rectangle is 1.2 times its width.

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