The rectangle is 25 percent longer than its width. Find the area of the rectangle if its perimeter is 54 cm.

1. Let’s say that the width of the rectangle is x cm.

2. The length of the rectangle is 25% greater than its width, so we find 25% of the width of the rectangle.

x / 100 * 25 = x * 0.25 = 0.25x.

3. The length of the rectangle will be (x + 0.25x) cm.

4. Let’s make an equation and find out what the width of the rectangle is if it is known that the perimeter of this rectangle is 54 cm.

x + x + (x + 0.25x) + (x + 0.25x) = 54;

x + x + x + 0.25x + x + 0.25x = 54;

4.5x = 54;

x = 54 / 4.5;

x = 12 cm.

5. Find out what the length of the rectangle is.

12 + 12 * 0.25 = 12 + 3 = 15 cm.

6. Let’s calculate the area.

12 * 15 = 180 cm ^ 2.

Answer: The area of the rectangle is 180 cm ^ 2.