The rectangle is 8 inches long and 4 inches wide. Find the area of a square with the same perimeter.

Let us find the perimeter of a rectangle, the length of which, according to the condition, is 8 dm, and the width = 4 dm, according to the formula:
P = 2a + 2b.
Since the opposite sides of such a figure are equal:
P = 2 * 8 + 2 * 4 = 16 + 8 = 24 dm.
because all sides of the square are equal, and the perimeter is 24 dm, we find what its 1 side is equal to:
24 dm / 4 = 6 dm
find the area of a square by the formula
S = a ^ 2
S = 6 ^ 2 = 36